How do you use Heron's formula to find the area of a triangle with sides of lengths #29 #, #25 #, and #12 #?
Area of triangle is
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To use Heron's formula to find the area of a triangle with sides of lengths 29, 25, and 12, follow these steps:

Calculate the semiperimeter (s) of the triangle: s = (a + b + c) / 2, where a, b, and c are the lengths of the sides of the triangle.

Use Heron's formula to find the area (A) of the triangle: A = sqrt(s * (s  a) * (s  b) * (s  c))
Substitute the values of the sides of the triangle into the formula:
a = 29, b = 25, c = 12
Calculate the semiperimeter (s):
s = (29 + 25 + 12) / 2 s = 33
Now, substitute s and the side lengths into Heron's formula:
A = sqrt(33 * (33  29) * (33  25) * (33  12)) A = sqrt(33 * 4 * 8 * 21) A = sqrt(5544) A ≈ 74.5 square units
Therefore, the area of the triangle with sides of lengths 29, 25, and 12 is approximately 74.5 square units.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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