How do you use Heron's formula to find the area of a triangle with sides of lengths #2 #, #5 #, and #5 #?
Use the Heron's formula
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To use Heron's formula to find the area of a triangle with sides of lengths 2, 5, and 5, you first need to calculate the semiperimeter ((s)) of the triangle. Then, you can use Heron's formula, which states that the area ((A)) of a triangle with side lengths (a), (b), and (c) is given by:
[ A = \sqrt{s(sa)(sb)(sc)} ]
where (s) is the semiperimeter, and (a), (b), and (c) are the lengths of the sides.
For the given triangle with side lengths 2, 5, and 5:
 Calculate the semiperimeter, (s), using the formula: (s = \frac{a + b + c}{2}).
 Substitute the side lengths into Heron's formula to find the area, (A).
Let's calculate:

( s = \frac{2 + 5 + 5}{2} = \frac{12}{2} = 6 )

( A = \sqrt{6(62)(65)(65)} = \sqrt{6(4)(1)(1)} = \sqrt{24} )
Therefore, the area of the triangle is ( \sqrt{24} ) square units.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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