How do you use Heron's formula to find the area of a triangle with sides of lengths #3 #, #2 #, and #4 #?
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from heron's law we know,
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To use Heron's formula to find the area of a triangle with sides of lengths (a), (b), and (c):

Calculate the semiperimeter, denoted as (s), which is half the perimeter of the triangle: [s = \frac{{a + b + c}}{2}]

Use Heron's formula to find the area, denoted as (A), where (s) is the semiperimeter, and (a), (b), and (c) are the lengths of the sides: [A = \sqrt{s(s  a)(s  b)(s  c)}]
For the given triangle with side lengths 3, 2, and 4:

Calculate the semiperimeter: [s = \frac{{3 + 2 + 4}}{2} = \frac{9}{2} = 4.5]

Use Heron's formula to find the area: [A = \sqrt{4.5(4.5  3)(4.5  2)(4.5  4)}] [A = \sqrt{4.5 \times 1.5 \times 2.5 \times 0.5}] [A = \sqrt{4.5 \times 3.75 \times 0.5}] [A = \sqrt{8.4375}] [A \approx 2.90]
So, the area of the triangle is approximately (2.90).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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