How do you use Heron's formula to find the area of a triangle with sides of lengths #1 #, #2 #, and #2 #?

Answer 1

#Area=0.9682458366# square units

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Answer 2

To use Heron's formula to find the area of a triangle with sides of lengths 1, 2, and 2, you first calculate the semi-perimeter, ( s ), using the formula:

[ s = \frac{{a + b + c}}{2} ]

where ( a ), ( b ), and ( c ) are the lengths of the triangle's sides.

In this case, ( a = 1 ), ( b = 2 ), and ( c = 2 ).

[ s = \frac{{1 + 2 + 2}}{2} = \frac{5}{2} ]

Next, use Heron's formula to find the area, ( A ), of the triangle:

[ A = \sqrt{s(s - a)(s - b)(s - c)} ]

[ A = \sqrt{\frac{5}{2} \times \frac{5}{2} \times \frac{3}{2} \times \frac{3}{2}} ]

[ A = \sqrt{\frac{225}{16}} ]

[ A = \frac{15}{4} ]

So, the area of the triangle is ( \frac{15}{4} ) square units.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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