How do you use Heron's formula to find the area of a triangle with sides of lengths #7 #, #5 #, and #8 #?
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To use Heron's formula to find the area of a triangle with side lengths 7, 5, and 8, you first need to calculate the semi-perimeter of the triangle. The semi-perimeter, denoted as ( s ), is calculated as the sum of all the side lengths divided by 2.
In this case, the side lengths are 7, 5, and 8. So, the semi-perimeter is:
[ s = \frac{7 + 5 + 8}{2} = \frac{20}{2} = 10 ]
Next, you can use Heron's formula to find the area of the triangle, which is given by:
[ A = \sqrt{s(s - a)(s - b)(s - c)} ]
Where:
- ( s ) is the semi-perimeter of the triangle.
- ( a ), ( b ), and ( c ) are the lengths of the sides of the triangle.
Substituting the values:
[ A = \sqrt{10(10 - 7)(10 - 5)(10 - 8)} ]
[ A = \sqrt{10(3)(5)(2)} ]
[ A = \sqrt{300} ]
[ A \approx 17.32 ]
So, the area of the triangle with side lengths 7, 5, and 8 is approximately 17.32 square units.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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