How do you use Heron's formula to find the area of a triangle with sides of lengths #9 #, #3 #, and #9 #?

Answer 1

#A=(9sqrt35)/4approx13.3112#

Heron's formula states that for a triangle with sides #a,b,c# and a semiperimeter #s=(a+b+c)/2#, the area of the triangle is

#A=sqrt(s(s-a)(s-b)(s-c))#

Here, we know that

#s=(9+3+9)/2=21/2#

which gives an area of

#A=sqrt(21/2(21/2-9)(21/2-3)(21/2-9))#

#A=sqrt(21/2(3/2)(15/2)(3/2))#

#A=sqrt((9^2xx7xx5)/4^2)#

#A=(9sqrt35)/4approx13.3112#

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Answer 2

Sophia Alfred

To use Heron's formula to find the area of a triangle with sides of lengths 9, 3, and 9, you first need to calculate the semi-perimeter of the triangle, which is the sum of the lengths of the three sides divided by 2. Then, you can use Heron's formula, which states that the area (A) of a triangle with side lengths a, b, and c and semi-perimeter s is given by the square root of s times (s - a) times (s - b) times (s - c), where s = (a + b + c) / 2. Plugging in the values for the sides of the triangle, you would calculate the semi-perimeter, then use it to find the area using Heron's formula.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.