# How do you use Heron's formula to determine the area of a triangle with sides of that are 14, 16, and 17 units in length?

The area of a triangle, according to Heron, is:

Let's compute the area now:

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To use Heron's formula, first calculate the semi-perimeter of the triangle by adding the lengths of all three sides and dividing by 2. In this case, the semi-perimeter is (14 + 16 + 17) / 2 = 23. Then, apply Heron's formula, which states that the area ( A ) of a triangle with side lengths ( a ), ( b ), and ( c ) is given by:

[ A = \sqrt{s(s-a)(s-b)(s-c)} ]

where ( s ) is the semi-perimeter, and ( a ), ( b ), and ( c ) are the lengths of the sides of the triangle.

So, plugging in the values:

[ A = \sqrt{23(23-14)(23-16)(23-17)} ] [ A = \sqrt{23(9)(7)(6)} ] [ A = \sqrt{23 \times 9 \times 7 \times 6} ] [ A = \sqrt{2646} ] [ A ≈ 51.51 , \text{units}^2 ]

Therefore, the area of the triangle is approximately ( 51.51 , \text{units}^2 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do I solve this problem?

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