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How do you use cross products to solve #s/11=30/110#?

Answer 1

Cross multiply to get #s=3#

We can use the cross multiplication formula.
Following the image's suggestions, we can plug in #s# for #a#, #11# for #b#, #30# for #c#, and #110# for #d#.

We'd multiply #a# and #d#, and #b# and #c#.

#a*d=s*110# and #b*c=11*30#.

#s*110=110s#, and #11*30=330#.

We'd then set the two values equal to each other: #110s=330#. We'd want to get #s# to its simplest form, so divide both sides by #110#.

#(110s)/ 110=s#, and #330/110=3#, so #s=3#.

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Answer 2

Ethan Adkins

To solve the equation ( \frac{s}{11} = \frac{30}{110} ) using cross products, you multiply the numerator of one fraction by the denominator of the other fraction and set them equal to each other. This process looks like this:

[ s \times 110 = 30 \times 11 ]

[ 110s = 330 ]

Then, to solve for ( s ), divide both sides of the equation by 110:

[ \frac{110s}{110} = \frac{330}{110} ]

[ s = 3 ]

So, ( s = 3 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.