How do you use cross products to solve #2/9=c/27#?

Answer 1

Just arrange the equation

#2/9 = c/27#
#2times27 = ctimes9#
#(2times27)/9 = c#
#2times3=c#
#6=c#
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Answer 2

c = 6

First we need to cross multiply. #2 xx 27 = 9 xx c#
Which gives us... #54 = 9c#
To make the next step easy, we will flip the equation #9c = 54#
Now we can find the value of c #c = 54 / 9#
#c = 6#
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Answer 3

#c=6#

#"given equal fractions then we can solve using "color(blue)"cross-products"#
#"that is "a/b=c/drArrbc=adlarrcolor(blue)"cross-products"#
#"applying this to "2/9=c/27" gives"#
#9c=2xx27#
#rArr9c=54#
#"divide both sides by 9"#
#(cancel(9) c)/cancel(9)=54/9#
#rArrc=6#
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Answer 4

To solve the equation 2/9 = c/27 using cross products:

  1. Multiply both sides of the equation by 27 to eliminate the denominator on the right side: 27 * (2/9) = 27 * (c/27).
  2. Simplify both sides: (27 * 2)/9 = c.
  3. Calculate the left side: (54)/9 = c.
  4. Simplify the left side: 6 = c.

So, the solution to the equation is c = 6.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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