# How do you the equation of the line that is perpendicular to the line 2x - 3y = 3 and passes through the point (-8, 2)?

When given a line in form

Use the given point to find the value of

Every perpendicular line has the following equation:

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To find the equation of the line perpendicular to the given line and passing through the point (-8, 2), we first need to determine the slope of the given line. Then, we find the negative reciprocal of that slope to get the slope of the perpendicular line. Next, we use the point-slope form of the equation of a line to find the equation of the perpendicular line. Finally, we simplify the equation into the desired form, usually slope-intercept or standard form.

Given line: 2x - 3y = 3 Slope of the given line: m = 2/3 Slope of the perpendicular line: Negative reciprocal of 2/3 = -3/2

Using the point-slope form of the equation of a line: y - y1 = m(x - x1)

Substitute the point (-8, 2) and the slope -3/2 into the equation: y - 2 = (-3/2)(x - (-8))

Simplify: y - 2 = (-3/2)(x + 8)

Expand and simplify: y - 2 = (-3/2)x - 12 y = (-3/2)x - 12 + 2 y = (-3/2)x - 10

Therefore, the equation of the line perpendicular to 2x - 3y = 3 and passing through the point (-8, 2) is y = (-3/2)x - 10.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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