How do you tell whether the ordered pair (2,-2) is a solution to #y<x-3, y> -x+1#?

Answer 1

see explanation.

Substitute the coordinates of the ordered pair into each inequality and check if they are true/false. If true then they are a solution.

#"using " x=2" and " y=-2#
#• y< x-3#
#rArr-2<2-3rArr-2<-1larr" TRUE"#
#• y> -x+1#
#rArr-2> -2+1rArr-2> -1larr" FALSE"#
#"Hence the ordered pair (2 ,-2)"#
#"is only a solution to " y< x-3#
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Answer 2
To determine if the ordered pair (2, -2) is a solution to the system of inequalities y < x - 3 and y > -x + 1, you need to check if both inequalities are true when x = 2 and y = -2. For the inequality y < x - 3: -2 < 2 - 3 -2 < -1 (true) For the inequality y > -x + 1: -2 > -2 + 1 -2 > -1 (false) Since the ordered pair (2, -2) satisfies the first inequality but not the second, it is not a solution to the system of inequalities.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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