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How do you take #-4 + 3a^2# from #7a - a^2#?

Answer 1

Eli Assouline

If you "take" #(-4+3a^2)# from #(7a-a^2)# you get #(4+7a-4a^2)#

To "take" A away from B, means to subtract A from B or, algebraically, #(B-A)#

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Answer 2

Isaiah Anthony

To take -4 + 3a^2 from 7a - a^2, you subtract each term of -4 + 3a^2 from the corresponding terms of 7a - a^2. This results in the expression 7a - a^2 - (-4) - 3a^2. Simplifying this expression yields 7a - a^2 + 4 - 3a^2. Then, combining like terms gives us 7a - 4a^2 + 4.

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Answer 3

Abigail Allen

To take ( -4 + 3a^2 ) from ( 7a - a^2 ), you simply subtract ( -4 + 3a^2 ) from ( 7a - a^2 ).

So, ( 7a - a^2 - (-4 + 3a^2) = 7a - a^2 + 4 - 3a^2 ).

Combine like terms:

( 7a - a^2 + 4 - 3a^2 = 7a - 3a^2 - a^2 + 4 ).

Then, simplify:

( 7a - 3a^2 - a^2 + 4 = 7a - 4a^2 + 4 ).

So, the result of taking ( -4 + 3a^2 ) from ( 7a - a^2 ) is ( 7a - 4a^2 + 4 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.