# How do you subtract #9/(x^2-9) - 5/ (x+3)#?

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Substitute (3) into (2) giving:

Substitute (4) into (1) giving:

Now both denominators have something in common so we can combine them

substituting (6) into (5) and rewriting the expression gives:

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To subtract the given expressions, we need to find a common denominator. The common denominator for the two expressions is (x+3)(x-3).

Next, we multiply the numerator and denominator of the first fraction, 9/(x^2-9), by (x+3) to get 9(x+3).

Similarly, we multiply the numerator and denominator of the second fraction, 5/(x+3), by (x-3) to get 5(x-3).

Now, we can rewrite the subtraction as a single fraction: (9(x+3) - 5(x-3))/(x+3)(x-3).

Expanding the numerator, we have (9x + 27 - 5x + 15)/(x+3)(x-3).

Combining like terms, we get (4x + 42)/(x+3)(x-3).

Therefore, the simplified expression is 4x + 42 divided by (x+3)(x-3).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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