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How do you solve #z( 6z - 5) ( z + 5) = 0#?

Answer 1

Julia Adams

distribute #z# then foil

#z(6z -5 )(z+5) = 0#

distribute z to the first parentheses term

#6z*z = 6z^2#

#(6z^2 -5z)(z+5)#

now we foil ( First - Outside - Inner - Last)

F #6z^2*z = 6z^3#

#6z^2*5= 30z^2#

I # -5z * z = -5z^2#

# -5z * 5 = -25z#

Now we just bring like terms together keep in mind the signs and the final answer should be

#6z^3 + 25z^2 - 25z#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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