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How do you solve #y = x² - 6x - 16#?

Answer 1

Isaiah Anthony

y-intercept # = -16#
x-intercepts #= 8# and #(-2)#
vertex is located at #(-3,-25)#

The answer depends upon for what kind of thing you want to solve.

The equation as stated is a general solution for #y# in terms of #x#

The answer above provides 3 common things you might be asked to solve for.

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Answer 2

Nathan Axel

To solve the equation ( y = x^2 - 6x - 16 ), you can follow these steps:

Rearrange the equation to standard quadratic form: ( x^2 - 6x - y - 16 = 0 ).
Use the quadratic formula: ( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} ), where ( a = 1 ), ( b = -6 ), and ( c = -y - 16 ).
Substitute the values of ( a ), ( b ), and ( c ) into the quadratic formula.
Solve for ( x ) by calculating both the positive and negative roots.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.