How do you solve #y=(x+2)^2-5#?

Answer 1

x= -2#+-sqrt5#

Solving the given equation would imply finding the roots of the quadratic on the right side. This can be done by making y=0 and solving for x

#(x+2)^2 -5=0#

#(x+2)^2=5#

x+2= #+- sqrt5#

x= -2#+- sqrt5#

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Answer 2

Abigail Allen

To solve the equation ( y = (x+2)^2 - 5 ), you can follow these steps:

Expand the squared term: [ y = (x+2)(x+2) - 5 ]
Simplify the expression: [ y = x^2 + 4x + 4 - 5 ]
Combine like terms: [ y = x^2 + 4x - 1 ]

This is the simplified form of the equation. If you need to solve for a specific value of ( y ) or ( x ), further steps may be required depending on the context of the problem.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.