# How do you solve #y = 4x - 3#, #y = 1# by graphing and classify the system?

See a solution process below:

To solve this by graphing, plot two points for each equation, draw a line through the two points, and note the intersection of the lines for each equation.

Formula 1:

Plot the two points after solving the equation for them, then draw a line through them:

graph{(x^2+(y+3)^2-0.04)((x-1)^2+(y-1)^2-0.04)=0 [-10, 10, -5, 5]

Equation 2:

graph{(y-1)(y-4x+3)((x+2)^2+(y-1)^2-0.04)((x-2)^2+(y-1)^2-0.04)=0 [-10, 10, -5, 5]

Find the intersection of the lines:

graph{x-1)^2+(y-1)^2-0.04)=0 [-10, 10, -5, 5]

The system of equations is regarded as consistent because it shares at least one point.

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To solve the system of equations y = 4x - 3 and y = 1 by graphing, you would plot both lines on the coordinate plane. The first line y = 4x - 3 has a slope of 4 and a y-intercept of -3. The second line y = 1 is a horizontal line passing through the y-coordinate 1. The point of intersection between these two lines represents the solution to the system. The system is classified as consistent and independent since it has exactly one solution.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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