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How do you solve #y/4 +2 = -1#?

Answer 1

Eva Adamson

#y = -12#

#=> y/4 + 2 = -1#

Subtract #2# from both the sides

#=> y/4\ cancel(+2)\ cancel(-2) = -1 - 2#

#=> y/4 = -3#

Multiply both sides by #4#

#=> y/cancel(4) × cancel(4) = -3 × 4#

#=> y = -12#

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Answer 2

Avery Alexander

#y=-12#

Resolve:

#y/4+2=-1#

Multiply both sides by #4#.

#y/color(green)cancel(color(black)(4))^1xxcolor(green)cancel(color(red)(4))^1+2xxcolor(red)4=-1xxcolor(red)4#

Make it simple.

#y+8=-4#

Subtract #8# from both sides.

#y+color(red)cancel(color(black)(8))-color(red)cancel(color(black)(8))=-4-8#

Make it simple.

#y=-12#

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Answer 3

Eva Adamson

To solve the equation y/4 + 2 = -1, first subtract 2 from both sides to isolate the y/4 term. This gives you y/4 = -1 - 2, which simplifies to y/4 = -3. Next, multiply both sides of the equation by 4 to get rid of the fraction. This yields y = -3 * 4, which simplifies to y = -12. So, the solution to the equation is y = -12.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.