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How do you solve #y-3<5y+1#?

Answer 1

Eli Assouline

#y> -1#

Move like terms to one side:

#y-5y<1+3#

#-4y<4#

When multiplying or dividing by the negative, make sure to flip the inequality sign:

#y> -1#

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Answer 2

Avery Alexander

#y<-1#

#y-3<5y + 1#

#y-y-3-1<5y + 1-1-y#

#-4/4>4/4y#

#-1>y#

#y<-1#

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Answer 3

Abigail Allen

To solve the inequality y - 3 < 5y + 1, follow these steps:

Subtract y from both sides: -3 < 4y + 1
Subtract 1 from both sides: -4 < 4y
Divide both sides by 4: -1 < y

So, the solution to the inequality is y > -1.

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Answer 4

Genesis Allen

To solve ( y - 3 < 5y + 1 ), follow these steps:

Subtract ( y ) from both sides to isolate the variable on one side of the inequality.
Subtract ( 1 ) from both sides to isolate the constant term on the other side of the inequality.
Simplify the expression.
Divide both sides by the coefficient of ( y ) to solve for ( y ).

[ y - 3 < 5y + 1 ]

[ -3 < 4y + 1 ]

[ -3 - 1 < 4y ]

[ -4 < 4y ]

[ \frac{-4}{4} < y ]

[ -1 < y ]

So, the solution is ( y > -1 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #y-3&lt;5y+1#?

How do you solve #y-3<5y+1#?