# How do you solve #y + 2/y = 1/y - 5#?

Multiply through by

Given:

Let's use the quadratic formula.

The discriminant is given by the formula:

Being positive but not a perfect square we can tell that our equations has two distinct irrational real roots.

The solutions are given by the formula:

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To solve the equation y + 2/y = 1/y - 5, we can start by multiplying both sides of the equation by y to eliminate the denominators. This gives us y^2 + 2 = 1 - 5y. Rearranging the equation, we have y^2 + 5y + 3 = 0. To solve this quadratic equation, we can factor it as (y + 3)(y + 1) = 0. Therefore, the solutions are y = -3 and y = -1.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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