How do you solve #y=1/3x + 2# and #y=4/3x 3# by graphing?
(3,1) is where they intersect
If you solve it algebraically you can check your graphing is correct
Equate both equations:
Subtract 2 from both sides:
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To solve the system of equations (y = \frac{1}{3}x + 2) and (y = \frac{4}{3}x  3) by graphing, plot both equations on the same graph and find the point(s) where they intersect.
Here's how you can do it:

For the first equation (y = \frac{1}{3}x + 2): Plot the yintercept at (0, 2). Use the slope of (1/3) to find another point, like (3, 3).

For the second equation (y = \frac{4}{3}x  3): Plot the yintercept at (0, 3). Use the slope of (4/3) to find another point, like (3, 7).

Plot both lines on the same graph.

Find the point(s) where the lines intersect. This point represents the solution to the system of equations.

If the lines do not intersect, it means the system has no solution.
Graphing the equations will visually show the intersection point or points, providing the solution to the system of equations.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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