How do you solve #x + y > 4 + x#?

Answer 1

Subtract #x# from both sides of the inequality to get #y>4#

This : #x+y>4+x# is called an inequality.

The solution you get after solving an inequality is called a set(or otherwise a range of values)

Here's how it goes : subtract #x# from both sides.
#x+y>4+x# becomes #color(red)x+ycolor(red)(-x)>4+color(red)(x-x) #
#rarrcolor(blue)(y>4)#

I have the right to subtract an entity from both sides of an inequality because, this action leaves the inequality the same(unchanged)

For example : #4+1<5 +1# is true.
Now if remove the #1# that's on either side, the condition is preserved.
That is, #4<5# is still true!
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Answer 2

Solve the inequality:
x + y > 4 + x

y > 4 The solution set of this inequality is the area above the horizontal line y = 4. Any point (x, y) in this area would satisfy this inequality regardless of the value of x.

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Answer 3

To solve the inequality ( x + y > 4 + x ), first, subtract ( x ) from both sides to simplify the expression. This yields ( y > 4 ). So, the solution to the inequality is ( y ) is greater than 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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