How do you solve #x=y+4# and #x=2y+8# using substitution?
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To solve the system of equations using substitution:
 Substitute ( x ) from the first equation into the second equation: ( y + 4 = 2y + 8 )
 Subtract ( y ) from both sides: ( 4 = y + 8 )
 Subtract 8 from both sides: ( 4 = y )
 Substitute ( y = 4 ) into the first equation to find ( x ): ( x = 4 + 4 )
 ( x = 0 )
So, the solution to the system of equations is ( x = 0 ) and ( y = 4 ).
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To solve the system of equations ( x = y + 4 ) and ( x = 2y + 8 ) using substitution, follow these steps:

Since both equations are solved for ( x ), set them equal to each other: ( y + 4 = 2y + 8 )

Now, solve for ( y ): ( y + 4  y = 2y + 8  y ) ( 4 = y + 8 )

Subtract 8 from both sides: ( 4  8 = y ) ( 4 = y )

Substitute the value of ( y ) back into one of the original equations to find ( x ). Using ( x = y + 4 ): ( x = 4 + 4 ) ( x = 0 )
Therefore, the solution to the system of equations is ( x = 0 ) and ( y = 4 ).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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