How do you solve x + y = 1 and 3x – y = 11?

Answer 1

#y=-2# and #x=3#.

Make #x# or #y# the subject from one equation and substitute it into the other; simultaneous equations are required.
#x=1-y#

Next

#3(1-y)-y = 11#
#3-3y-y=11#
#3–4y=11#
#4y=-8#
#y=-2#
Re-substitute #y=-2# into either equation to determine #x#.
#x-2=1#
#x=3#
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Answer 2

To solve the system of equations x + y = 1 and 3x - y = 11:

  1. Solve one equation for one variable in terms of the other variable.
  2. Substitute the expression obtained in step 1 into the other equation.
  3. Solve the resulting equation for the remaining variable.
  4. Use the value found in step 3 to find the value of the other variable.
  5. Check the solution by substituting the values into both original equations to ensure they are satisfied.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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