How do you solve #x/(x^2-8)=2/x#?
Move everything from the denominator to the numerator first; to do this, multiply each side's denominator by the LCM.
which gives us the following:
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To solve the equation x/(x^2-8) = 2/x, we can start by cross-multiplying to eliminate the fractions. This gives us x * x = 2 * (x^2-8). Simplifying further, we have x^2 = 2x^2 - 16. Rearranging the equation, we get x^2 - 2x^2 = -16. Combining like terms, we have -x^2 = -16. Dividing both sides by -1, we get x^2 = 16. Taking the square root of both sides, we have x = ±4. Therefore, the solutions to the equation are x = 4 and x = -4.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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