How do you solve #x+ \frac { 2} { 5} \geq 3#?
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To solve (x + \frac{2}{5} \geq 3), first, subtract (\frac{2}{5}) from both sides to isolate (x). This gives (x \geq 3 - \frac{2}{5}). Then, subtract (\frac{2}{5}) from 3: (3 - \frac{2}{5} = \frac{15}{5} - \frac{2}{5} = \frac{13}{5}). So, the solution is (x \geq \frac{13}{5}).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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