How do you solve #(x-8)(x-1)=0#?
One way of seeing this is using some logic and math.
If you have a product that equals zero, as in this case, you must agree that at least one of the factors is zero.
Another way is distributing these factors. To distribute, you need to multiply each term of the first by all the terms in the second, as follows:
And now let's find its roots. I'll use Bhaskara here.
:)
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To solve the equation ((x-8)(x-1) = 0), you set each factor to zero and solve for (x):
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Set (x-8 = 0) and solve for (x): (x - 8 = 0) (x = 8)
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Set (x-1 = 0) and solve for (x): (x - 1 = 0) (x = 1)
So, the solutions to the equation are (x = 8) and (x = 1).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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