How do you solve #(x-6/5)/x-(x-10 1/2)/(x-5)=(x+21)/(x^2-5x)#?

Answer 1

#x = 50/11#

Rewriting the right side of the equation, The common denominator is #x^2 - 5x#
#((x-5)(x-6/5))/(x^2 - 5x) - (x(x-10.5))/(x^2 - 5x) = (x+21)/(x^2 - 5x)#
Multiplying both sides of the equation by #x^2 - 5x#,
#(x-5)(x-6/5) - x(x-10.5) = x+21#
Simplifying further, #(x^2 - 31/5x + 6) - (x^2 - 10.5x) = x+21# #x^2 - 31/5x - x^2 + 10.5x - x=21-6# #-33/10x = 15# #x = 50/11#
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Answer 2

To solve the equation (x-6/5)/x-(x-10 1/2)/(x-5)=(x+21)/(x^2-5x), we can follow these steps:

  1. Simplify the fractions on both sides of the equation.
  2. Find a common denominator for all the fractions.
  3. Multiply each fraction by the common denominator to eliminate the denominators.
  4. Simplify the resulting equation.
  5. Solve for x by isolating it on one side of the equation.
  6. Check the solution by substituting it back into the original equation.

By following these steps, you can find the solution to the given equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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