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How do you solve #x/6 - (3x)/2 = 16/3#?

Answer 1

Eva Abramson

#x=-4#

#x/6-(3x)/2=16/3#

Multiply all terms by #6#.

#(6xxx/6)-(6xx(3x)/2)=6xx16/3#

#(cancel6xxx/cancel6)-(3cancel6xx(3x)/cancel2)=2cancel6xx16/cancel3#

#x-9x=32#

#-8x=32#

Divide both sides by #8#.

#-x=4# or #x=-4#

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Answer 2

Julia Adams

To solve the equation x/6 - (3x)/2 = 16/3, we can start by finding a common denominator for the fractions. The common denominator is 6. Multiplying each term by 6, we get 6(x/6) - 6((3x)/2) = 6(16/3). Simplifying, we have x - 3x = 32. Combining like terms, we get -2x = 32. Dividing both sides by -2, we find x = -16. Therefore, the solution to the equation is x = -16.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.