# How do you solve # (x-5)^2=4#?

Solution:

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#{:("if " x-5=-2,color(white)("xxx"),"if "x=+2), ("then " x=3,,"then "x=7) :}#

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To solve the equation (x - 5)^2 = 4, you would take the square root of both sides and then solve for x.

(x - 5)^2 = 4 √(x - 5)^2 = ±√4 x - 5 = ±2 x = 5 ± 2

So, the solutions are x = 5 + 2 = 7 and x = 5 - 2 = 3.

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To solve ( (x-5)^2 = 4 ):

- Take the square root of both sides of the equation.
- Consider both the positive and negative square roots when taking the square root.
- Solve for ( x ) by adding 5 to both sides of the equation and considering both positive and negative solutions.

The solutions are ( x = 5 + 2 ) and ( x = 5 - 2 ), which simplify to ( x = 7 ) and ( x = 3 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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