How do you solve #(x+4)^3(x+2)^2=0#?

Answer 1

Chloe Alexander

#x = - 4, - 2#

We have: #(x + 4)^(3) (x + 2)^(2) = 0#

Using the null factor law:

#Rightarrow (x + 4)^(3) = 0#

#Rightarrow x + 4 = 0#

#therefore x = - 4#

#or#

#Rightarrow (x + 2)^(2) = 0#

#Rightarrow x + 2 = 0#

#therefore x = - 2#

Therefore, the solutions to the equation are #x = - 4# and #x = - 2#.

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Answer 2

Sophie Adams

To solve the equation ( (x+4)^3(x+2)^2 = 0 ), we set each factor equal to zero and solve for ( x ).

Setting ( (x+4)^3 = 0 ), we find: ( x+4 = 0 ) ( x = -4 )

Setting ( (x+2)^2 = 0 ), we find: ( x+2 = 0 ) ( x = -2 )

Therefore, the solutions to the equation ( (x+4)^3(x+2)^2 = 0 ) are ( x = -4 ) and ( x = -2 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.