How do you solve #x+3y=y+110# for y?

Answer 1

#y=(110-x)/2#

Solve #x+3y=y+110# for #y#.
Subract #x# from both sides of the equation.
#3y=y+110-x#
Subtract #y# from both sides.
#3y-y=110+x#
Simplify #3y-y# to #2y#.
#2y=110+x#
Divide both sides by #2#.
#y=(110-x)/2#
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Answer 2

To solve ( x + 3y = y + 110 ) for ( y ), you can start by isolating the variable ( y ) on one side of the equation. Subtract ( y ) from both sides of the equation:

( x + 3y - y = 110 )

This simplifies to:

( x + 2y = 110 )

Then, subtract ( x ) from both sides of the equation:

( x - x + 2y = 110 - x )

This simplifies to:

( 2y = 110 - x )

Finally, divide both sides of the equation by 2 to solve for ( y ):

( \frac{2y}{2} = \frac{110 - x}{2} )

This gives:

( y = \frac{110 - x}{2} )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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