How do you solve #x+3y=-1#, #y=x+1#?
For a problem like this you would use substitution method.
So:
(Apply algebraic solving)
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To solve the system of equations x + 3y = -1 and y = x + 1:
- Substitute the expression for y from the second equation into the first equation.
- Solve for x.
- Once you find the value of x, substitute it back into one of the original equations to find the value of y.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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