How do you solve #x / 30 - 1/(5x) = 1/6#?

Answer 1

#x=-1 and x=6#

Write the equivalent equation, obtained by multiplying all terms by #30x#:
#x^2-6=5x and x!=0#
#x^2-5x-6=0#
#x=(5+-sqrt(25-4(-6)))/2#
#x=(5+-sqrt(49))/2#
#x=(5+-7)/2#
#x=-1 and x=6#
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Answer 2

To solve the equation x / 30 - 1/(5x) = 1/6, we can start by finding a common denominator for the fractions. The common denominator is 30x. Multiplying each term by 30x, we get:

x * (30x / 30) - (1/(5x)) * (30x / 30) = (1/6) * (30x / 30)

This simplifies to:

x^2 - 6 = 5x

Rearranging the equation:

x^2 - 5x - 6 = 0

Factoring the quadratic equation:

(x - 6)(x + 1) = 0

Setting each factor equal to zero:

x - 6 = 0 or x + 1 = 0

Solving for x:

x = 6 or x = -1

Therefore, the solutions to the equation are x = 6 and x = -1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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