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How do you solve # (x+3)(x-3) > 0#?

Answer 1

Hazel Anglin

#x > 3#

#(x + 3)(x - 3) > 0#

#x² - 3x + 3x - 9 > 0#

#x² - 9 > 0#

#x² > 9#

#x > sqrt9#

#x > 3#

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Answer 2

Avery Alexander

To solve \( (x+3)(x-3) > 0 \), you need to find the intervals where the expression is greater than zero. This can be done by identifying the critical points where the expression equals zero, which are \( x = -3 \) and \( x = 3 \), and then testing the intervals between these points. The solution is \( x < -3 \) or \( x > 3 \).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve # (x+3)(x-3) &gt; 0#?

How do you solve # (x+3)(x-3) > 0#?