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How do you solve #x-(3/x) = -2#?

Answer 1

Eva Adamson

You can start by lowest common denominator

#(x*x-3*1)/x=-2# #(x^2-3)/x=-2# #x^2-3=-2x# #x^2+2x-3=0#

Now, just find the roots:

(I'll use Bhaskara)

#(-2+-sqrt(4-4(1)(-3)))/2# #(-2+-4)/2#

#x_1=-3# #x_2=1#

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Answer 2

Eva Adamson

To solve the equation x - (3/x) = -2, we can follow these steps:

Multiply both sides of the equation by x to eliminate the fraction: x(x) - (3/x)(x) = -2(x).
Simplify the equation: x^2 - 3 = -2x.
Rearrange the equation by moving all terms to one side: x^2 + 2x - 3 = 0.
Factor the quadratic equation: (x + 3)(x - 1) = 0.
Set each factor equal to zero and solve for x: x + 3 = 0 or x - 1 = 0.
Solve for x in each equation: x = -3 or x = 1.

Therefore, the solutions to the equation x - (3/x) = -2 are x = -3 and x = 1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.