How do you solve #(x - 3) - 5x = - 3( x + 3)#?

Question

Nathan Axel · Accepted Answer

#x=6#

#"distribute brackets on both sides of the equation"#

#x-3-5x=-3x-9#

#rArr-4x-3=-3x-9#

#"add 3x to both sides"#

#-4x+3x-3=cancel(-3x)cancel(+3x)-9#

#rArr-x-3=-9#

#"add 3 to both sides"#

#-xcancel(-3)cancel(+3)=-9+3#

#rArr-x=-6#

#"multiply both sides by "-1#

#rArrx=6#

#color(blue)"As a check"#

This value is the solution if you substitute it into the equation and both sides come out equal.

#"left "=6-3-(5xx6)=3-30=-27#

#"right "=-3(6+3)=-3xx9=-27#

#rArrx=6" is the solution"#

Kennedy Adams · Answer

By arranging the equation

Eliminate the parenthesis: #x-3-5x = -3x - 9# #-4x - 3 = -3x -9# #-4x + 3x = -9 + 3# #-x = -6# #x=6# This is your answer #x=6#

Eva Abramson · Answer

undefined To solve the equation $(x - 3) - 5x = -3(x + 3)$, you would follow these steps:

1. First, distribute the negative sign in front of the parentheses on the right side of the equation:
$$x - 3 - 5x = -3x - 9$$

2. Next, combine like terms on both sides of the equation:
$$x - 5x - 3 = -3x - 9$$
$$-4x - 3 = -3x - 9$$

3. Then, isolate the variable terms on one side and the constant terms on the other side:
$$(-4x + 3x) = -9 + 3$$
$$-x = -6$$

4. To solve for $x$, multiply both sides of the equation by -1 to get rid of the negative sign in front of $x$:
$$x = 6$$

5. Finally, verify the solution by substituting $x = 6$ back into the original equation:
$$(6 - 3) - 5(6) = -3(6 + 3)$$
$$(3) - 30 = -3(9)$$
$$-27 = -27$$

Since both sides of the equation are equal when $x = 6$, the solution is correct. Therefore, $x = 6$ is the solution to the equation.