How do you solve #x/3 - 5 =3(x-2)#?

Answer 1

#x = 3/8#

#x/3 -5 = 3(x-2)" "larr(xx3# to cancel the denominator)
#3xxx/3 -3xx5 = 3xx3(x-2)#
#x -15 = 9x-18#
#18-15 = 9x-x#
#3 = 8x#
#x= 3/8#
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Answer 2

To solve the equation ( \frac{x}{3} - 5 = 3(x-2) ), follow these steps:

  1. Distribute 3 across ( (x-2) ) to get ( 3x - 6 ).
  2. Combine like terms to get ( \frac{x}{3} - 5 = 3x - 6 ).
  3. Multiply both sides by 3 to eliminate the fraction, resulting in ( x - 15 = 9x - 18 ).
  4. Subtract ( x ) from both sides to get ( -15 = 8x - 18 ).
  5. Add 18 to both sides to isolate ( x ), resulting in ( 3 = 8x ).
  6. Divide both sides by 8 to solve for ( x ), yielding ( x = \frac{3}{8} ).

So, the solution to the equation is ( x = \frac{3}{8} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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