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How do you solve #(x+3)/3 = 6/x#?

Answer 1

Genesis Allen

# x= 3 or x= -6 #

#{x+3}/3 = 6/x#

#x(x+3) = 6(3)#

# x^2 + 3x = 18#

#x^2 +3 x - 18 = 0#

# (x- 3)(x+6) = 0#

# x= 3 or x= -6 #

Check:

#x=3#

#{3+3}/3 = 2 #

#6/3 = 2 quad sqrt #

#{-6 + 3}/3= -1 #

#6/-6 = -1 quad sqrt #

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Answer 2

Genesis Allen

To solve the equation (x+3)/3 = 6/x, you can start by cross-multiplying to eliminate the fractions. This gives you (x+3)x = 18. Expanding the left side of the equation, you get x^2 + 3x = 18. Rearranging the equation, you have x^2 + 3x - 18 = 0. Factoring or using the quadratic formula, you find that the solutions are x = -6 and x = 3.

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Answer 3

Savannah Anderson

To solve the equation (\frac{x + 3}{3} = \frac{6}{x}):

Multiply both sides of the equation by (3x) to eliminate the denominators.
Simplify the equation.
Solve for (x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.