How do you solve #x/3+2=x/2-1# and check for extraneous solutions?
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To solve the equation x/3 + 2 = x/2 - 1:
- Multiply every term by the least common denominator (LCD) to clear the fractions.
- Simplify the resulting equation to isolate the variable x.
- Check the solutions obtained by plugging them back into the original equation to ensure they are not extraneous.
The solution to the equation is x = 12. Checking this solution, we find that it is not extraneous.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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