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How do you solve #(x-3)^2=3(x-3)#?

Answer 1

Ethan Adkins

#x=6#

#x=3#

#(x-3)^2=3(x-3)#

#x^2-6x+9=3x-9#

#x^2-9x+18=0#

#(x-6)(x-3)=0#

Hence

#x=6" "# or #" "x=3#

Hope it helped!

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Answer 2

Avery Alexander

To solve the equation (x-3)^2 = 3(x-3), first expand (x-3)^2 to get x^2 - 6x + 9. Then distribute 3 to get 3x - 9. Now set the equation equal to zero: x^2 - 6x + 9 - 3x + 9 = 0. Combine like terms: x^2 - 9x + 18 = 0. Now, factor the quadratic equation or use the quadratic formula to find the solutions for x.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.