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How do you solve #(x/3) = (12/(x-5))#?

Answer 1

Genesis Allen

Cross-multiply: #x^2 - 5x = 36# #x^2-5x-36=0# #(x-9)(x+4) = 0# #x=9; x=-4#

To check: #(9/3) =(12/(9-5))# #3 = 3#

#(-4/3) = (12/(-4-5))# #(-4/3) = -4/3#

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Answer 2

Julia Adams

To solve the equation (x/3) = (12/(x-5)), we can cross-multiply to eliminate the fractions. This gives us x(x-5) = 12 * 3. Expanding the left side of the equation, we get x^2 - 5x = 36. Rearranging the equation, we have x^2 - 5x - 36 = 0. Factoring the quadratic equation, we find (x-9)(x+4) = 0. Therefore, the solutions are x = 9 and x = -4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.