# How do you solve #x^3-11x^2-8x+88>=0#?

The solution is

Factor by grouping.

Hopefully this helps!

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To solve the inequality (x^3 - 11x^2 - 8x + 88 \geq 0), you need to find the intervals where the expression is greater than or equal to zero. This can be done by factoring, finding critical points, and testing intervals.

- Factor the polynomial if possible.
- Find the critical points by setting the expression equal to zero and solving for (x).
- Test intervals determined by the critical points to determine where the expression is greater than or equal to zero.

Since factoring may not always be straightforward, you might need to use numerical methods or graphing to find approximate solutions.

Without further context on the polynomial, such as restrictions on (x) or exact values of (x) for which the inequality holds, this is the general approach.

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