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How do you solve #x^2 + 8x + 16 = 9#?

Answer 1

Savannah Anderson

#x=-1# or #x=-7#

#x^2+8x+16=9#

Subtract #9# from both sides.

#x^2+8x+7=0#

Factorise.

#x^2+7x+x+7=0#

#x(x+7)+1(x+7)=0#

#(x+1)(x+7)=0#

#x+1=0# and #x+7=0#

#x=-1# and #x=-7#

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Answer 2

Ethan Adkins

To solve the equation (x^2 + 8x + 16 = 9), you first subtract 9 from both sides of the equation to get (x^2 + 8x + 7 = 0). Then, you can factor the quadratic expression (x^2 + 8x + 7) as ((x + 7)(x + 1) = 0). Next, you set each factor equal to zero, so you have (x + 7 = 0) and (x + 1 = 0). Solving these equations, you find (x = -7) and (x = -1). Therefore, the solutions to the equation (x^2 + 8x + 16 = 9) are (x = -7) and (x = -1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.