How do you solve #x^2 - 8x = -16#?

Answer 1

Eli Assouline

x has equal roots : #x=4#

#x^2-8x+16=0 or (x-4)^2 =0 or (x-4)(x-4)=0 :. x=4 and x=4#[Ans]

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Answer 2

Jameson Allen

To solve the equation x^2 - 8x = -16, you can follow these steps:

Move all terms to one side of the equation to set it equal to zero: x^2 - 8x + 16 = 0
Factor the quadratic equation: (x - 4)(x - 4) = 0
Apply the zero-product property: x - 4 = 0 x = 4
Check for extraneous solutions: Substitute x = 4 into the original equation: 4^2 - 8(4) = -16 16 - 32 = -16 -16 = -16

The solution x = 4 is valid.

So, the solution to the equation x^2 - 8x = -16 is x = 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.