How do you solve #x^2 +8x +16=0#?
The solution is
The source of the discriminant is:
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To solve the equation ( x^2 + 8x + 16 = 0 ), you can use the quadratic formula, which states that for an equation in the form ( ax^2 + bx + c = 0 ), the solutions are given by ( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} ).
For this specific equation:
- ( a = 1 )
- ( b = 8 )
- ( c = 16 )
Plug these values into the quadratic formula and solve for ( x ):
[ x = \frac{{-8 \pm \sqrt{{8^2 - 4 \cdot 1 \cdot 16}}}}{{2 \cdot 1}} ] [ x = \frac{{-8 \pm \sqrt{{64 - 64}}}}{2} ] [ x = \frac{{-8 \pm \sqrt{{0}}}}{2} ] [ x = \frac{{-8 \pm 0}}{2} ] [ x = \frac{{-8}}{{2}} ]
Thus, the solution is ( x = -4 ) with a multiplicity of 2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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