How do you solve #x^2 + 8 = 28#?
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To solve the equation (x^2 + 8 = 28), follow these steps:
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Subtract 8 from both sides of the equation: [x^2 = 20]
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Take the square root of both sides of the equation: [x = \pm \sqrt{20}]
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Simplify the square root of 20: [x = \pm \sqrt{4 \times 5} = \pm 2 \sqrt{5}]
So, the solutions to the equation are (x = 2\sqrt{5}) and (x = -2\sqrt{5}).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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