How do you solve #(x+2)/6=(x-1)/12#?

Answer 1

#x=-5#

By cross multiplication, #12(x+2)=6(x-1)# #12x+24=6x-6# #12x-6x=-24-6# #6x=-30# Divide both sides by #color(red)(6)# #cancel(6x)/cancelcolor(red)(6) = (-30)/color(red)(6)# #x=-5#

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Answer 2

Julia Adams

To solve the equation (x+2)/6 = (x-1)/12, cross multiply to eliminate the denominators. Then, solve for x.

Here's the step-by-step process:

Multiply both sides of the equation by 6 and 12 to eliminate the denominators: 6 * (x+2)/6 = 6 * (x-1)/12
Simplify: (x+2) * 12 = (x-1) * 6
Expand: 12x + 24 = 6x - 6
Move the terms involving x to one side of the equation and constants to the other side: 12x - 6x = -6 - 24
Combine like terms: 6x = -30
Divide both sides by 6 to solve for x: x = -5

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.