Home > Algebra > Comparing Methods for Solving Quadratics

How do you solve #x^2 + 5x - 8 = 4x + 4#?

Answer 1

x= 3, x = -4

#y = x^2 + x - 12 = 0# Find 2 numbers knowing sum (-1 = -b) and product (c = -12). They are the factor pair (3, -4). The 2 real roots are: 3 and -4.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Nathan Axel

To solve the equation x^2 + 5x - 8 = 4x + 4, you first need to rearrange it into the standard quadratic form by moving all terms to one side:

x^2 + 5x - 4x - 8 - 4 = 0

Simplify the equation:

x^2 + x - 12 = 0

Now, you can solve this quadratic equation by factoring, completing the square, or using the quadratic formula.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.