How do you solve #x^2 - 5x - 6 = 0#?

Answer 1

-1 and 6

#y = x^2 - 5x - 6 = 0# Since (a - b + c = 0), use shortcut. The 2 real roots are: (- 1) and (-c/a = 6)
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Answer 2

To solve the quadratic equation (x^2 - 5x - 6 = 0), you can use the quadratic formula:

[x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}]

where (a), (b), and (c) are the coefficients of the quadratic equation (ax^2 + bx + c = 0).

For the given equation, (a = 1), (b = -5), and (c = -6).

Substitute these values into the quadratic formula:

[x = \frac{{-(-5) \pm \sqrt{{(-5)^2 - 4(1)(-6)}}}}{{2(1)}}]

Simplify:

[x = \frac{{5 \pm \sqrt{{25 + 24}}}}{2}]

[x = \frac{{5 \pm \sqrt{49}}}{2}]

[x = \frac{{5 \pm 7}}{2}]

So, the solutions are:

[x_1 = \frac{{5 + 7}}{2} = 6]

[x_2 = \frac{{5 - 7}}{2} = -1]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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