How do you solve #x^2 - 5x - 6 = 0#?
-1 and 6
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To solve the quadratic equation (x^2 - 5x - 6 = 0), you can use the quadratic formula:
[x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}]
where (a), (b), and (c) are the coefficients of the quadratic equation (ax^2 + bx + c = 0).
For the given equation, (a = 1), (b = -5), and (c = -6).
Substitute these values into the quadratic formula:
[x = \frac{{-(-5) \pm \sqrt{{(-5)^2 - 4(1)(-6)}}}}{{2(1)}}]
Simplify:
[x = \frac{{5 \pm \sqrt{{25 + 24}}}}{2}]
[x = \frac{{5 \pm \sqrt{49}}}{2}]
[x = \frac{{5 \pm 7}}{2}]
So, the solutions are:
[x_1 = \frac{{5 + 7}}{2} = 6]
[x_2 = \frac{{5 - 7}}{2} = -1]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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